Wave questions II
Consider the musical note G, 392 Hz. Find the following:
1. The frequencies of the next two G's, one and two octaves above.
2. The frequency of the G one octave lower than 392 Hz.
3. The frequency of G#, one semi-tone (piano key or guitar fret) above this G.
4. The frequency of A#, 3 semi-tones above G.
5. The wavelength of the 392 Hz sound wave, assuming that the speed of sound is 340 m/s.
answers:
1. 392 x 2 = 784 Hz; 392 x 4 = 1568 Hz
2. 392/2 = 196 Hz
3. 392 x 1.0594 = 415 Hz
4. 392 x 1.0594 x 1.0594 x 1.0594 (or 392 x 1.0594^3) = 466 Hz
5. wavelength = speed / frequency = 340/392 = 0.87 m
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